Question

a feather is dropped on the moon from a height of 1.4 meters.the acceleration of the moon is 1.67 m/s determine the time for the feather to fall on the surface of

the moon

Answer 1

See previous post.

Answer 2

90seconds

Answer 3

[AI-generated answer — Explain Bot]

To determine the time it takes for the feather to fall on the surface of the moon, you can use the kinematic equation for linear motion:

s = ut + (1/2)at^2

Where:
s = distance or height (1.4 meters in this case)
u = initial velocity (0, since the feather is dropped and not given an initial velocity)
a = acceleration (1.67 m/s)
t = time

In this case, the equation becomes:

1.4 = 0 * t + (1/2) * 1.67 * t^2

Simplifying the equation:

1.4 = (1/2) * 1.67 * t^2

To solve for t, we can rearrange the equation:

t^2 = (2 * 1.4) / 1.67

t^2 = 2.80 / 1.67

t^2 ≈ 1.6766

Taking the square root of both sides:

t ≈ √1.6766

t ≈ 1.295 seconds

Therefore, it takes approximately 1.295 seconds for the feather to fall on the surface of the moon.