Ben has 8 square tiles. Each tile has a width of 9 inches. He lays the tiles down in a long row. What is the perimeter of the rectangle of tiles?

P = 2L + 2W

P = 2(72) + 2(9)

P = 144 + 18

P = 162 inches = 13 feet 6 inches

Thank you! :) I appreciate you using your time to answer my and other peoples' questions.

You're very welcome. :-)

To find the perimeter of the rectangle formed by the tiles, we need to know the length and width of the rectangle. However, you only provided the width of the tiles.

If we assume that all the tiles are lined up side by side to form a long row, then the length of the rectangle would be the total width of all the tiles combined. Since each tile has a width of 9 inches and there are 8 tiles, the total width would be 9 inches multiplied by 8, which equals 72 inches.

Now that we have the length and width of the rectangle (72 inches and 9 inches, respectively), we can calculate the perimeter. The perimeter of a rectangle is found by adding the lengths of all four sides. In this case, two opposite sides have a length of 72 inches and the other two opposite sides have a length of 9 inches.

So, the perimeter of the rectangle of tiles would be (72 + 72 + 9 + 9) inches, which equals 162 inches.