Write a menu driven program using a conditional structure.
Certainly, here's an example of a menu-driven program using a conditional structure in Python:
```python
# Function to display the menu options
def display_menu():
print("Menu:")
print("1. Option 1")
print("2. Option 2")
print("3. Option 3")
print("4. Quit")
# Function to perform option 1
def option_1():
print("Performing Option 1...")
# Function to perform option 2
def option_2():
print("Performing Option 2...")
# Function to perform option 3
def option_3():
print("Performing Option 3...")
# Main program
while True:
display_menu() # Display the menu options
choice = input("Enter your choice (1-4): ")
if choice == "1":
option_1()
elif choice == "2":
option_2()
elif choice == "3":
option_3()
elif choice == "4":
print("Quitting...")
break
else:
print("Invalid choice! Please enter a number from 1 to 4.")
```
In this program:
1. First, we define a function `display_menu()` that prints the available options on the console.
2. Then, we define three functions (`option_1()`, `option_2()`, and `option_3()`) that will be called when the user selects the respective options.
3. Inside the main program, we have a while loop that repeatedly displays the menu, prompts the user for their choice, and performs the corresponding action based on the user's input.
4. The user can choose options 1, 2, 3 to call the respective functions, or choose option 4 to quit the program.
Note that in this example, the user's input is assumed to be a number (1, 2, 3, or 4). If the user enters an invalid choice (other than 1-4), the program displays an error message and prompts for a valid choice again.