# physics

An 8 hour exposure to a sound level of 95.0 dB may cause hearing damage. What energy in joules falls on a 0.850 cm diameter eardrum so exposed?

I try to use
k = IAT = (1*10^-3)(0.0085^2)(8*3600)=0.00208

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1. L=10 log₁₀ (I/I₀)
I₀= 10⁻¹² W/m²
I/I₀ = 10^(L/10)=
=10^(L/10)=
I= I₀•10^(L/10) =
=10⁻¹²•10^(95/10) =3.16•10⁻³W/m²
E= I•A•t=I•πr²•t=
=3.16•10⁻³•π•0.0085²•8•3600 =2.07•10⁻²J

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posted by Elena
2. Elena, thank you for your help, but the answer is not correct.

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posted by Justin

E=(3.16^-3)[(π*0.0085/2)^2](8*3600)=0.00516 J

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posted by Justin

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