Write an equation in slope-intercept form for a line that passes through the given point and is perpendicular to the given line.
1. y=3;(4,-2)
The y = 3 line is parallel to the x axis so the perpendicular line you want is parallel to the y axis. That means x must be a constant in the equation for that line. Since it goes through the point (x = 4, y = -2), the equation is x = 4. (y can be anything, including -2)
What line is perpendicular to y=7/8-2
To find the equation in slope-intercept form for a line that is perpendicular to the given line, we first need to determine the slope of the given line. Since the equation of the given line is y = 3, we can see that the slope is zero.
For a line that is perpendicular to a line with slope zero, the slope of the perpendicular line will be undefined (or infinite). The equation of this perpendicular line will have an x-value that remains constant and a variable y-value.
Given that the line passes through the point (4,-2), the equation can be written as x = 4.
In slope-intercept form, an equation is typically written as y = mx + b, where m is the slope and b is the y-intercept. Since the slope of the perpendicular line is undefined, the equation cannot be written in this form. Instead, the equation x = 4 represents a line that is perpendicular to the given line y = 3 and passes through the point (4,-2).