) A body with an initial velocity of 5ms‾¹ accelerate uniformly at the rate of 16 cm s‾²

over a distance of 200 m. Calculate: (i) the acceleration in m s‾² (ii) its final velocity in m s‾¹

a = 16 cm/s^2

= .16 m/s^2

s = v0*t + 1/2 at^2, so
5t + .08t^2 = 200
t = 27.7

v = v0+at
= 5 + .16*27.7
= 9.4 m/s