Can someone please explain how to do this

An equilibrium mixture at 225∘C contains 8.0×10−2M NH3 and 0.20M H2 for the reaction
3H2(g)+N2(g)←→2NH3(g)

If the Kc at this temperature is 1.7×102, what is the equilibrium concentration of N2?

Kc = {NH3]^2 / [H2]^3 [N2]

[N2] = (8.0×10^−2M)^2 / (0.20M)^3 (1.7×10^2)