The length of a rectangle is twice the width. The area is 200 yd^2. Find the length and the width.
Length times width = area
2x * x = 200
Solve for x.
I hope this helps. Thanks for asking.
To find the length and width of the rectangle, let's set up some equations based on the given information.
Let's denote the width of the rectangle as x. Since the length is twice the width, the length can be represented as 2x.
The formula for the area of a rectangle is given by length multiplied by width, so we have:
Area = Length × Width
Substituting the values we have:
200 = (2x) × x
Simplifying this equation, we get:
200 = 2x^2
Now, we need to solve for x. To do this, let's divide both sides of the equation by 2:
100 = x^2
Taking the square root of both sides, we find:
√100 = √x^2
10 = x
So, the width of the rectangle is 10 yards.
Now, we can find the length by substituting the value of x:
Length = 2x = 2(10) = 20 yards
Therefore, the length of the rectangle is 20 yards and the width is 10 yards.
Let's assume the width of the rectangle is "x" yards.
According to the given information, the length of the rectangle is twice the width, so the length would be "2x" yards.
The formula to find the area of a rectangle is length × width, so in this case, the area is given as 200 square yards.
Therefore, we can write the equation as:
(x)(2x) = 200
Simplifying the equation:
2x² = 200
Dividing both sides of the equation by 2:
x² = 100
Taking the square root of both sides:
√(x²) = √100
x = ±10
Since the width cannot be negative, the width of the rectangle is 10 yards.
To find the length, we substitute the value of the width (x) into the expression "2x":
2(10) = 20
So, the length of the rectangle is 20 yards.