find the domain, target, and rule of the inverse functions:
1. f(x)=(x+3)/(5x+2)
2. g(x)=1/square root of 2x-1
y = (x+3)/(5x+2)
5xy+2y = x+3
(5y-1)x = 3-2y
x = (3-2y)/(5y-1)
So, the inverse function is (3-2x)/(5x-1)
y = 1/√(2x-1)
y^2 = 2x-1
x = (y^2+1)/2
So, g^-1(x) = (x^2+1)/2
You can probably figure out the rest.