A car that weifgs 15000 n is initially moving at 60 km/hr when the brakes are applied. The cae is broight to a stop in 30 m. Assuming the force applied by the brakes is constant, determine the magnitude of the braking force.

Vo = 60km/hr = 60000m/3600s = 16.67 m/s.

V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d
a = (0-(16.67)^2)/60 = -4.63 m/s^2.

Wt. of car = m*g = 15000 N.
mass = 15000/9.8 = 1531 kg

F = m*a = 1531 * -4.63 = -7.1 N.

To determine the magnitude of the braking force, we can use the equation of motion that relates force, mass, acceleration, and distance.

The equation we will use is:

Force (F) = (mass (m) × acceleration (a)) / distance (d)

First, we need to convert the mass of the car (given in newtons) into kilograms, as the equation requires the mass to be in kilograms. The weight of the car is given as 15000 N. We can convert this weight to mass using the acceleration due to gravity (approximately 9.8 m/s^2).

Mass (m) = Weight (W) / Acceleration due to gravity (g)

Substituting the given values, we have:

Mass (m) = 15000 N / 9.8 m/s^2

Now we can determine the distance the car traveled during braking. The given distance is 30 m.

Substituting the values into the equation, we have:

Force (F) = (Mass (m) × Acceleration (a)) / Distance (d)
= (m × a) / d

We are given the initial velocity of the car (60 km/hr), but we need to convert it to meters per second (m/s) for consistency.

Velocity (v) = 60 km/hr × (1000 m/1 km) / (3600 s/1 hr)
= 16.67 m/s

Since the car comes to a stop, the final velocity (vf) is 0 m/s. The acceleration (a) is given by the equation:

vf^2 = vi^2 + 2ad

Substituting the values, we have:

0 = (16.67 m/s)^2 + 2(a)(30 m)

Now we can solve for the acceleration (a):

(16.67 m/s)^2 = 2(a)(30 m)
a = [(16.67 m/s)^2] / (2 × 30 m)
a = 9.23 m/s^2

Now we have all the values required to determine the magnitude of the braking force:

Force (F) = (Mass (m) × Acceleration (a)) / Distance (d)
= (m × a) / d

Substituting the values, we get:

Force (F) = (15000 N / 9.8 m/s^2) × 9.23 m/s^2 / 30 m
= 35,897.96 N

Therefore, the magnitude of the braking force is approximately 35,898 N.