Two balls are approaching each other head-on. Their velocities are +11.9 and -10.5 m/s. Determine the velocity of the center of mass of the two balls if (a) they have the same mass and (b) if the mass of one ball (v = 11.9 m/s) is twice the mass of the other ball (v = -10.5 m/s).

Well, it seems like these balls are having a speedy tête-à-tête!

(a) If the balls have the same mass, we can calculate the velocity of the center of mass by using the equation:

Vcm = (m1v1 + m2v2) / (m1 + m2)

Since the velocity of the first ball (v1) is +11.9 m/s and the velocity of the second ball (v2) is -10.5 m/s, and assuming their masses (m1 and m2) are the same, we can plug in these values:

Vcm = (m1 * 11.9 + m1 * -10.5) / (m1 + m1)
= 1.4 m/s

Therefore, the velocity of the center of mass is 1.4 m/s.

(b) Now, let's consider a scenario where one ball has twice the mass of the other ball. Let's call the mass of the lighter ball m and the mass of the heavier ball 2m.

Using the same formula as before, we can now calculate the velocity of the center of mass:

Vcm = (m * 11.9 + 2m * -10.5) / (m + 2m)
= (-7.2m) / (3m)
= -7.2/3 m/s

Therefore, in this case, the velocity of the center of mass is -7.2/3 m/s, or approximately -2.4 m/s.

So, my dear friend, those are the velocities of the center of mass for both scenarios. Keep those balls rollin'!

To determine the velocity of the center of mass of the two balls, we can use the formula:

Velocity of center of mass = (m1 * v1 + m2 * v2) / (m1 + m2)

(a) If the balls have the same mass:
m1 = m2
v1 = +11.9 m/s
v2 = -10.5 m/s

Plug in the values into the formula:
Velocity of center of mass = (m1 * v1 + m2 * v2) / (m1 + m2)
= (m1 * 11.9 + m1 * (-10.5)) / (m1 + m1)
= (11.9m1 - 10.5m1) / (2m1)
= 1.4 m1 / 2m1
= 1.4 / 2
= 0.7 m/s

Therefore, the velocity of the center of mass of the two balls, if they have the same mass, is 0.7 m/s.

(b) If one ball has twice the mass of the other:
m1 = 2m2
v1 = +11.9 m/s
v2 = -10.5 m/s

Plug in the values into the formula:
Velocity of center of mass = (m1 * v1 + m2 * v2) / (m1 + m2)
= (2m2 * 11.9 + m2 * (-10.5)) / (2m2 + m2)
= (23.8m2 - 10.5m2) / (3m2)
= 13.3m2 / 3m2
= 13.3 / 3
= 4.4 m/s

Therefore, the velocity of the center of mass of the two balls, if one ball has twice the mass of the other, is 4.4 m/s.

To determine the velocity of the center of mass of the two balls, we can use the concept of the conservation of momentum. The principle of the conservation of momentum states that the total momentum of a system remains constant if no external forces act on it.

Let's start with part (a), where the masses of both balls are equal.

(a) The velocity of the center of mass (Vcm) can be calculated using the equation:

Vcm = (m1 * v1 + m2 * v2) / (m1 + m2)

Where:
- Vcm is the velocity of the center of mass.
- m1 and m2 are the masses of the balls.
- v1 and v2 are the velocities of the balls.

Since the masses of both balls are the same, let's consider them as m1 = m2 = m. Also, the given velocities are +11.9 m/s and -10.5 m/s.

Vcm = (m * 11.9 + m * (-10.5)) / (m + m)
Vcm = (11.9 - 10.5) / 2

Vcm = 1.4 / 2
Vcm = 0.7 m/s

Therefore, when the two balls have the same mass, the velocity of the center of mass is 0.7 m/s.

Now let's move on to part (b), where the mass of one ball is twice the mass of the other ball.

In this case, let's consider the mass of one ball as m1 and the mass of the other ball as m2, where m2 = 2m1.

To find the velocity of the center of mass, we can use the same equation:

Vcm = (m1 * v1 + m2 * v2) / (m1 + m2)

Substituting the given values, m1 = m and m2 = 2m, and v1 = 11.9 m/s, and v2 = -10.5 m/s, we have:

Vcm = (m * 11.9 + 2m * (-10.5)) / (m + 2m)
Vcm = (11.9m - 21m) / 3m

Vcm = -9.1m / 3m
Vcm = -3.03 m/s

Therefore, when the mass of one ball is twice the mass of the other ball, the velocity of the center of mass is -3.03 m/s.

the total momentum of the two balls is

m v1 + m v2
which is the total mass times the final v

in the first case
m v1 + m v2 = (2 m) v
m (v1+v2) = 2 m v
2 v = 11.9-10.5 = 1.4
v = .7

in the second case
2 m ( 11.9) + m (-10.5) = 3 m v
23.8 - 10.5 = 3 v
solve for v