A 9.00 V storage battery is connected to three resistors, 4.25 Ω, 11.0 Ω, and 21.0 Ω, respec-tively. The resistors are joined in series.
Calculate the equivalent resistance
can someone answer this please?
R=R1+R2+R3
IF YOU ADD THEM ALL UP AND DIVIDE BY 69 UR ANSWER IS STILL WRONG LOL
To calculate the equivalent resistance, we need to add up the resistances of the individual resistors in the series.
The formula to calculate the equivalent resistance for resistors in series is:
Req = R1 + R2 + R3 + ...
In this case, we have three resistors with resistances given as:
R1 = 4.25 Ω
R2 = 11.0 Ω
R3 = 21.0 Ω
Now, we can substitute these values into the formula to find the equivalent resistance:
Req = 4.25 Ω + 11.0 Ω + 21.0 Ω
Req = 36.25 Ω
Therefore, the equivalent resistance (Req) is 36.25 Ω.
Sure, I can help with that! To calculate the equivalent resistance in a series circuit, you simply add up the resistances of the individual resistors. In this case, you have three resistors with resistance values of 4.25 Ω, 11.0 Ω, and 21.0 Ω.
To find the equivalent resistance, you can add these three resistances together:
Equivalent resistance (Req) = Resistance1 + Resistance2 + Resistance3
Req = 4.25 Ω + 11.0 Ω + 21.0 Ω
Now, let's calculate the value:
Req = 36.25 Ω
Therefore, the equivalent resistance is 36.25 Ω.