a 5 g mixture of natural gas containing ch4 and c2h4 was burnt in excess of oxygen yielding 14.5 g of co2 and h2o.What is the weight of ch4 and co2 in the mixture

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  1. CH4 + 2O2 ==> CO2 + 2H2O
    C2H4 + 3O2 ==> 2CO2 + 2H2O

    Let x = mass CH4
    and y = mass C2H4
    You need two equations.
    (eqn 1) is total mass = 5g
    (eqn 2) is (mass CO2+H2O from CH4) + (mass CO2+H2O from C2H4) = 14.5g
    Now convert those into x and y and solve. I have let mm stand for molar mass below.
    (eqn 1) is x + y = 5
    (eqn 2) is
    [x(mmCO2/mmCH4)+x(2*mmH2O/mmCH4)]+y(2*mmCO2/mmC2H4)+y(2mmH2O)/mmC2H4] = 14.5g
    Solve for x = mass CH4
    y = mass C2H4.
    Post your work if you get stuck.

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  2. I am unable to solve the equations. Can you put up the equations too. The answer is a bit weird.

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  3. Am so sorry but I really not understand this 🙏

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