Write the standard form of the equation where p=π and o=7π/12
no idea what "p" and "o" represent, or which trig function is required.
The o has a diagonal line through it if that helps. I don't know about the p and that's why I'm confused.
To write the standard form of an equation, we typically use the equation:
y = A*cos(Bx - C) + D
Given that p = π and o = 7π/12, we can substitute the values into the equation to find the standard form.
Since p represents the period of the cosine function, we can use the formula p = 2π/B, where B is the coefficient of x. Therefore, in this case, 2π/B = π, which implies B = 2.
Since o represents the phase shift or the horizontal shift of the graph, we can use the formula o = C/B, where C is the phase shift. Therefore, in this case, C/2 = 7π/12, which implies C = 14π/12 or C = 7π/6.
Thus, the standard form equation becomes:
y = A*cos(2x - 7π/6) + D
Note that A and D are the amplitude and vertical shift, respectively, which we did not have values for in the given information.