A 1500 kg automobile is traveling up to 20 degree incline at a speed of 6 m/s. If the driver wishes to stop his car in a distance of 5m,determine the frictional force at pavement which must be supplied by rear wheels.
Ek = 0.5m*V^2 *h - = 750 * 6^2 = 27,000 J.
Wt. = Fg = 1500kg * 9.8N/kg = 14,700 N.
Ep = Fg * h = 27000-Fk*d
14700*5*sin20 = 27000-Fk*5
25138.5 = 27000-5Fk
5Fk = 27000-25138.5 = 1861.5
Fk = 372 N.