Chemistry Honors

A 0.25 mol sample of n204 dissociates and comes to equilibrium in a 1.5 L flask at 100 degrees C. The reaction is N2O4 > 2 NO2. The Kc at 100 degrees C is 0.36. What are the equilibrium concentrations of NO2 and N2O4?

asked by Marie Genvieve
  1. 0.25 mol/1.5L = 0.167M which I would round to 0.17. (Note: you may wish to carry an extra place and round the answer at the end to two significant figures. Follow your profs advice on this.)
    ........N2OP4 ==> 2NO2
    I.......0.167.....0
    C.......-x........2x
    E.....0.167-x....2x

    Kc = (NO2)^2/(N2O4)
    0.36 = (2x)^2/(0.167-x)
    Solve for x and 2x.

    posted by DrBob222

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry

    N204 (l) Delta Hf (kJ/mol) = -20 E cell S (J/mol.K) = 209 N204(g) Delta Hf (kJ/mol) = 10 E cell S (j/mol.k) = 304.1 Given the following data, determine the temperature at which n2o4 (l) and n204 (g) can exist in equilibrium? a. 42
  2. Chemistry!

    Consider the equilibrium system: N204 (g) = 2 NO2 (g) for which the Kp = 0.1134 at 25 C and deltaH rx is 58.03 kJ/mol. Assume that 1 mole of N2O4 and 2 moles of NO2 are introduced into a 5 L contains. What will be the equilibrium
  3. chemistry

    Nitrosyl bromide decomposes according to the following equation. 2NOBr (g)(equilibrium arrow) 2NO (g) + Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained
  4. chem class

    Nitrosyl bromide decomposes according to the following equation. 2NOBr (g)(equilibrium arrow) 2NO (g) + Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained
  5. chemistry

    The equilibrium constant (Kc) for the gas phase reaction 2 NH3 N2 + 3 H2 is 3.0 x 10-3 at some temperature. The reaction is started by placing a 0.040-mol sample of ammonia in an empty one-liter flask. When equilibrium is
  6. Chemistry

    A 1.500 mol sample of PCL5 dissociates at 160C and 1.00 atm to give 0.203 mol of PCL3 at equilibrium. What is the composition of the final reaction mixture?
  7. Chemistry

    PLEASE fully explain these...I've already tried to figure them out and failed terribly... thanks so much 4. 5.6 x 10-6 mol of A and 5 x 10-5 mol of B are mixed in a 200 mL flask. The system is represented by the equation: At
  8. Chemistry

    a 1.00-mol sample of phosphorus pentachloride placed in 10.0-L reaction flask and allowed to come to equilibrium at 250 degrees celsius; PCL5(g) = PCL3(g) Cl2(g) if the amount of chlorine in the equilibrium mixture is0.470 mol,
  9. Chemistry II

    The equlibrium constant Kc for the reaction: has the value of 4.00 at 500K. If a mixture of 1.00 mol CO and 1.00 mol H2O is allowed to reach equilibrium at this temperature in a 1.00L flask, calculate the equilibrium
  10. CHEM- need help ASAP

    An equilibrium mixture in a 10.0 L flask contains 7.0 mol HI(g) and 1.0 mol each of I2(g) and H2(g). If 2.5 mol H2, 5.0 mol I2 and 2.0 mol HI are added to that equilibrium mixture how many moles of each gas will be present when

More Similar Questions