solve (-2y)^2(3x^3)
I totally don't get this problem. Does my answer come out with x and y ? how do I eliminate?
I don't get it either, since there is nothing to "solve".
"Solving" requires an equation.
if you wanted to simplify it , it would be
(4y^2)(3x^3)
= 12 x^3 y^2
=(-2)^2 y^1 * (3x^3)
= 4(3)y^2 x^3
=12y^2 x^3
To solve the expression (-2y)^2(3x^3), we will simplify it step by step.
First, let's simplify (-2y)^2. To raise a negative number to the power of 2, we square both the negative sign and the squared number.
(-2y)^2 = (-2)^2 * y^2 = 4y^2
Next, we multiply the simplified term 4y^2 by 3x^3:
4y^2 * 3x^3 = 12x^3y^2
The final simplified expression is 12x^3y^2.
Now, regarding your question about eliminating x and y:
If you are trying to solve this expression for x and y, there is nothing to eliminate here since the original expression does not contain any equations or constraints related to x and y.
However, if you have specific values for x and y, you can substitute those values into the simplified expression 12x^3y^2 to calculate the final numerical answer.