What is the volume in liters of 5.0moles methane gas, CH4, at 20∘C and 1.40atm ?
Use PV = nRT
T must be in kelvin.
P in atm if R = 0.08206 L*atm/mol*K
To find the volume of a gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
To convert Celsius to Kelvin, we need to add 273.15. So, the temperature in Kelvin is 20 + 273.15 = 293.15 K.
The ideal gas constant, R, is 0.0821 L·atm/(mol·K).
Now we can plug in the values into the equation:
PV = nRT
V = (nRT) / P
V = (5.0 moles * 0.0821 L·atm/(mol·K) * 293.15 K) / 1.40 atm
By performing the calculation, we get:
V = (125.93275 L·atm) / 1.40 atm
V = 89.95267857 L
Therefore, the volume of 5.0 moles of methane gas at 20∘C and 1.40 atm is approximately 89.95 liters.