How much hot air in SCFM is needed to heat up water from 60F to boiling point. The hot air is 350F.

To calculate the amount of hot air needed to heat up water, we can use the following equation:

Q = m * Cp * ΔT

Where:
Q is the heat energy required (in joules)
m is the mass of water (in kilograms)
Cp is the specific heat capacity of water (in joules per kilogram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)

First, let's convert the temperatures from Fahrenheit to Celsius:

60°F = (60 - 32) * (5/9) ≈ 15.6°C
350°F = (350 - 32) * (5/9) ≈ 176.7°C

Next, let's determine the mass of water we are trying to heat. This information is not provided in the question, so we will assume a value. Let's say we have 1 kilogram of water (which is approximately equal to 1 liter).

Now, we need to calculate the change in temperature (ΔT):

ΔT = Final temperature - Initial temperature
ΔT = boiling point - 60

The boiling point of water at standard atmospheric pressure is 100°C.

ΔT = 100 - 15.6 ≈ 84.4°C

Finally, we need to determine the specific heat capacity of water (Cp). The specific heat capacity of water is approximately 4,186 joules per kilogram per degree Celsius.

Now, we can plug the values into the equation:

Q = m * Cp * ΔT
Q = 1 kg * 4,186 J/(kg°C) * 84.4°C

Calculating this multiplication will give us the heat energy required (Q) in joules.

To convert the heat energy from joules to SCFM (standard cubic feet per minute) of hot air, we need to know the specific heat capacity of the hot air. Since this information is not provided in the question, we cannot provide a direct answer in SCFM without further data.