How many kilos of ammonia (N1H2)are contained in 600L of a solution that is8% NC13 by volume
To determine the number of kilograms of ammonia (NH3) contained in 600L of a solution that is 8% NH3 by volume, we need to follow these steps:
Step 1: Calculate the volume of ammonia in the solution
To find the volume of NH3 in the solution, we multiply the total volume by the percentage of NH3 in the solution. In this case, the total volume is 600L, and the solution is 8% NH3:
Volume of NH3 = 600L * 8% = 600L * 0.08
Step 2: Convert the volume of ammonia to mass
To convert the volume of ammonia to mass, we need to know the density of ammonia. The density of ammonia can vary depending on temperature and pressure conditions. The standard density of ammonia at room temperature and pressure is approximately 0.771 grams per liter (g/L).
Mass of NH3 = Volume of NH3 * Density of NH3
Now, let's perform the calculations:
Mass of NH3 = (600L * 0.08) * 0.771 g/L
Step 3: Convert mass from grams to kilograms
To convert the mass from grams to kilograms, divide the mass by 1000:
Mass of NH3 in kilograms = (600L * 0.08 * 0.771 g/L) / 1000
Finally, evaluate the expression:
Mass of NH3 in kilograms = (48.48 g) / 1000 = 0.04848 kg
Therefore, there are approximately 0.04848 kilograms (48.48 grams) of ammonia (NH3) in a 600L solution that is 8% NH3 by volume.