Question

1. what is the 6th root of 8j^6k^3m^3n?

2. What is the fourth root of 4f^2g^2?

Answer 1

(8j^6k^3m^3n)^(1/6)

= 8^(1/6) j k^(1/2) m^(1/2) m^(1/6)
= √2 j √k √m n^(1/6)
= j√(2km) n^(1/6)

(4f^2 g^2)^(1/4)
= √2 √f √g
= √(2fg)