Calculus

Find the absolute extrema of the function on the interval [2, 9]. (Round your answers to the nearest hundredth.)
g(x)=x/(ln(x))
Absolute minimum: at x =
Absolute maximum: at x =

asked by Anonymous

Respond to this Question

First Name

Your Answer

Similar Questions

  1. Calculus (pleas help!!!)

    Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute
  2. Calculus (pleas help!!!)

    Find the absolute maximum and absolute minimum values of the function f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals. Enter -1000 for any absolute extrema that does not exist. (A) Interval = [1,4] Absolute
  3. Applied Calculus

    Find the absolute extrema of the function on the interval [2,3]. (Round your answers to the nearest hundredth.) Absolute Minimum ___ at x=___ Absolute Maximum ___ at x=___
  4. Calculus

    Find the absolute maximum and absolute minimum values of the function f(x)=x^3+6x^2-63x+4 on each of the indicated variables. Enter DNE for does not exist. (A) Interval = [-8,0] Absolute maximum = Absolute minimum = (B) Interval =
  5. math calculus

    Find the absolute extrema of the function on the closed interval. Use a graphing utility to verify your results. (Round your answers to two decimal places. If an answer does not exist, enter DNE.) g(x) = (x^2 − 4)^2/3,
  6. Calculus

    Find the absolute extrema of the function. (Round your answer to three decimal places.) f(x) = xe-x2 on [0,2] Absolute maximum value: at x = Absolute minimum value: at x =
  7. Calculus

    Find the absolute extrema of the function. (Round your answer to three decimal places.) f(x) = xe^-x2 on [0,2] Absolute maximum value: at x = Absolute minimum value: at x =
  8. Math(Calculus)

    Im having a real difficult time solving this question. Find the absolute extrema of the function. h(x) = e^x^(2) - 4 on [-2,2] Absolute maximum value: at x = Absolute minimum value: at x =
  9. calculus

    2) Let g(s)= t(4−t)^1/2 on the interval [0,2]. Find the absolute maximum and absolute minimum of g(t) on this interval. Enter DNE if the absolute maximum or minimum does not exist. The absolute max occurs at t= . The
  10. calculus

    Find the absolute maximum and absolute minimum values of f on the given interval. (Round all answers to two decimal places.) f(t) = t + cot(t/2)

More Similar Questions