You run a titration using HCI as the sample with 3.56M KOH as the titrant. Calculate the concentration of the HCI if the sample size were 25 mL, and if the volume of the titrant used were 29.6 mL.
Vb*Mb=Va*Ma
25*3.56=29.6*Molarityacid
To calculate the concentration of the HCI (hydrochloric acid) sample, you need to use the principles of titration. Titration involves neutralizing an acid with a known concentration with a base of known concentration. The balanced chemical equation for the reaction between hydrochloric acid (HCI) and potassium hydroxide (KOH) is:
HCI + KOH → H2O + KCl
From the balanced equation, you can see that the ratio between HCI and KOH is 1:1. This means that one mole of HCI reacts with one mole of KOH.
Given:
- Volume of KOH used (V1) = 29.6 mL
- Concentration of KOH (C1) = 3.56 M
- Volume of HCI sample (V2) = 25 mL
To calculate the concentration of HCI (C2), use the formula:
C1V1 = C2V2
Substituting the given values:
(3.56 M) * (29.6 mL) = C2 * (25 mL)
Solving for C2:
C2 = (3.56 M * 29.6 mL) / 25 mL
C2 ≈ 4.23 M
Therefore, the concentration of the HCI sample would be approximately 4.23 M if the sample size were 25 mL and the volume of the titrant used were 29.6 mL.