The parallel sides of a trapezium are 10m and 14m. If the area of the trapezium is 130 square meter, what is the distance between the parallel sides? Convert the answer into square yards.
Area of a trapezium:
A = (b1 + b2)*h/2
where:
b1 & b2 = lengths of the parallel sides
h = height or the distance between the parallel sides
Substituting,
130 = (10+14)*h/2
260 = 24*h
h = 260/24
h = ? (units in m)
Hope this helps~ :)
perimeter of isosceles trapezium
To find the distance between the parallel sides of a trapezium, we need to use the formula for the area of a trapezium. The formula is:
A = (b1 + b2) * h / 2
Where:
- A is the area of the trapezium
- b1 and b2 are the lengths of the parallel sides
- h is the distance between the parallel sides
In this case, we have the following values:
- b1 = 10m
- b2 = 14m
- A = 130 square meters
Let's plug the values into the formula and solve for h:
130 = (10 + 14) * h / 2
First, simplify the equation:
130 = 24h / 2
Next, multiply both sides by 2 to get rid of the fraction:
260 = 24h
Now, divide both sides by 24 to solve for h:
h = 260 / 24
Simplifying this fraction gives us:
h = 10.8333...
Therefore, the distance between the parallel sides is approximately 10.8333 meters.
To convert this distance into square yards, you need to know the conversion factor between meters and yards. Since 1 yard is equal to 0.9144 meters, we can use this conversion factor to convert the distance:
10.8333 meters * (1 yard / 0.9144 meters) = 11.87 yards (rounded to two decimal places)
So, the distance between the parallel sides of the trapezium is approximately 11.87 square yards.