What are the spectator ions in the following complete ionic equation: Ba2+(aq)+2I−(aq)+2Na+(aq)+SO2−4(aq)→BaSO4(s)+2I−(aq)+2Na+(aq). Thank you so much!!!
Well, isn't this equation a real circus! Let's see who's just spectating from the sidelines. In this equation, the spectator ions would be ions that haven't undergone any changes. So, drumroll please... the spectator ions are 2Na+ and 2I-! They're just enjoying the show, not participating in any chemical shenanigans. But don't worry, they'll have a chance to shine in the grand finale.
To identify the spectator ions in a chemical equation, you need to compare the ions on both sides of the equation. The spectator ions are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the equation is:
Ba^2+(aq) + 2I^-(aq) + 2Na+(aq) + SO4^2-(aq) → BaSO4(s) + 2I^-(aq) + 2Na+(aq)
Since the Na+(aq) and I^-(aq) ions appear on both sides of the equation, they are the spectator ions. Therefore, the spectator ions in the given equation are Na+ and I-.
To determine the spectator ions in a complete ionic equation, you need to identify the ions that appear on both sides of the equation and do not undergo any chemical changes. These ions are called spectator ions because they are only spectators and do not participate directly in the chemical reaction.
In the given equation: Ba2+(aq) + 2I−(aq) + 2Na+(aq) + SO2−4(aq) → BaSO4(s) + 2I−(aq) + 2Na+(aq)
The spectator ions are Na+(aq) and I−(aq).
This is because Na+ and I- ions appear on both sides of the equation and remain in their original ionic forms without undergoing any chemical changes. They are present as reactants and products but are not directly involved in the reaction. Therefore, they are simply spectators.
Note that Ba2+ and SO2-4 ions undergo a chemical change and participate in the formation of the solid compound BaSO4. These ions are not the spectator ions in this reaction.
To find the spectator ions just look at what can be canceled on each side of the equation. Ba2+ cannot.
2I- can.
SO4^2- can not(although you made a typo there in the post).
2Na+ can.
The net ionic equation is
Ba^2+(aq) + SO4^2-(aq) ==> BaSO4(s)
Everything else is a spectator ion.