Question

The initial temperature of a bomb calorimeter is 28.50°C. When a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°C. If the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 J/(g°C), how much heat is absorbed by the reaction?

Answer 1

yes

Answer 2

23.2

Answer 3

HA! GOT EEM

Answer 4

1,470 J

Answer 5

[AI-generated answer — Explain Bot]

To calculate the amount of heat absorbed by the reaction, we can use the equation:

q = m * c * ΔT

Where:
q = heat absorbed by the reaction
m = mass of the calorimeter
c = specific heat capacity of the calorimeter
ΔT = change in temperature

Let's plug in the values:

m = 1.400 kg
c = 3.52 J/(g°C) = 3520 J/(kg°C) (since 1 kg = 1000 g)
ΔT = 27.45°C - 28.50°C = -1.05°C (since the temperature decrease)

Now, let's substitute the values into the equation and calculate the heat absorbed by the reaction:

q = 1.400 kg * 3520 J/(kg°C) * (-1.05°C)
q = -5164.4 J

The negative sign indicates that heat is being released by the reaction. Therefore, the amount of heat absorbed by the reaction is 5164.4 J.