The sum of 3 numbers is 45. The first number is 4 times the second, while the third is 9 more than the second. Create an equation and solve.
a = first number
b = second number
c = third number
a = 4 b
c = b + 9
a + b + c = 45
4 b + b + b + 9 = 45
6 b + 9 = 45 Subtract 9 to both sides
6 b + 9 - 9 = 45 - 9
6 b = 36 Divide both sides by 6
6 b / 6 = 36 / 6
b = 6
a = 4 b
a = 4 * 6 = 24
c = b + 9
c = 6 + 9 = 15
First numer 24 , second number 6 , third number 15
a + b + c = 45
24 + 6 + 15 = 45
45 = 45
x = 2nd number
4x + x + (x + 9) = 45
6x + 9 = 45
6x = 36
x = 6
x+y+z=45
x=4y
z=y+9
4y+y+y+9=45
6y=36
y=6
...
thank you now i understand , i got the answer but i made a mistake on the equation
To solve this problem, we need to create equations based on the given information, and then solve them to find the values of the numbers. Let's start by assigning variables to each number.
Let's call the second number "x". Since the first number is 4 times the second, the first number can be represented as 4x. Similarly, the third number is 9 more than the second, so it can be represented as x + 9.
We are given that the sum of these three numbers is 45, so we can create the equation:
4x + x + (x + 9) = 45
Now, we can solve this equation to find the value of x, which represents the second number:
Combining like terms, we have:
6x + 9 = 45
Subtracting 9 from both sides of the equation:
6x = 36
Dividing both sides by 6:
x = 6
So, the second number is 6.
Now, we can find the values of the other two numbers:
The first number is 4 times the second number:
First number = 4 * 6 = 24
The third number is 9 more than the second number:
Third number = 6 + 9 = 15
Therefore, the three numbers are 24, 6, and 15.