how much work done if lina lift a package that weight 5.5 to a height of 0.5 m?
Indicate your specific subject in the "School Subject" box, so those with expertise in the area will respond to the question.
If you mean 5.5 kg and not newtons:
w = mg = 5.5 * 9.81 = 54 Newtons
54 * .5 = 27 Joules
To calculate the work done, you can use the formula:
Work = Force × Distance × cos(θ)
In this case, Lina is lifting a package, so the force applied is equal to the weight of the package. Given that the weight of the package is 5.5 kg, we can calculate the force:
Force = mass × gravity
The acceleration due to gravity is approximately 9.8 m/s^2. Therefore:
Force = 5.5 kg × 9.8 m/s²
Next, we need to determine the distance. In this case, the package is being lifted to a height of 0.5 m, so the distance is 0.5 m.
Finally, we need to find the angle θ between the applied force (vertical lift) and the direction of motion. In this case, the force and motion are in the same direction, so θ = 0 degrees. Therefore, cos(θ) = cos(0) = 1.
Now we can calculate the work:
Work = (Force) × (Distance) × cos(θ)
= (5.5 kg × 9.8 m/s²) × 0.5 m × 1
= 26.95 Joules
Therefore, the work done by Lina in lifting the package to a height of 0.5 m is 26.95 Joules.