math

Two cars leave at the same time from towns that are 460 miles apart and travel toward each other. They meet after 4 hours. Find the rate of each car if one car travels 13 miles per hour faster than the other.

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asked by Monica
  1. x + x + 13 =460/4

    2x + 13 = 115

    2x + 13 -13 = 115. -13

    2x = 102

    2x/2 = 102/2

    x = 51

    x + 13
    = 64

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    posted by Kuai
  2. define your variables:

    let the rate of the the slower car be x mph
    then the rate of the faster car is x+13 mph

    They both drive for 4 hours

    distance covered by slower car = 4x
    distance covered by faster car = 4(x+13)

    4x + 4(x+13) = 460
    8x 408
    x = 51

    slower car went 51 mph
    faster car went 64 mph

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    posted by Reiny

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