Is average speed (u) the same as root mean square velocity? I found a formula for root mean square velocity which I know is also used for average speed:
(3RT/MM)^1/2
Is that right?
I don't know what that is supposed to be an average OF, but is all likelihood it is a root mean square. The mean or average speed is not the same.
Are you sure you did not mean to write
[3 R T/ M ]^(1/2) ?
That is the room mean square speed of an ideal gas. M is the molar mass of the molecule.
Yes, that's what I meant. My book denotes molar mass as MM. Thank you
Question at what temperature The most probable velocity of nitrogen gas at 27degree celcious would be trippled
927 degree C
You're welcome! I'm glad I could help clarify the formula for you. The formula you provided, (3RT/MM)^1/2, is indeed correct for calculating the root mean square velocity of an ideal gas. In this formula, R represents the ideal gas constant and T represents the temperature. MM represents the molar mass of the gas molecule.
The root mean square velocity is a measure of the average velocity of gas particles in a sample. It is different from the average speed. The average speed considers the magnitude of the velocities of all the particles in a sample, whereas the root mean square velocity takes into account both the magnitudes and the directions of the velocities.
To determine if the given formula is used for average speed or root mean square velocity, we can examine the formula itself. The presence of the square root operation indicates that it is likely calculating a root mean square value, as the square root is a necessary step to obtain the root mean square value.
Remember, the average speed is the total distance traveled divided by the total time taken, while the root mean square velocity is calculated using the given formula, which considers temperature and molar mass.
I hope this explanation helps! Let me know if you have any further questions.