# Physics

The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm?

ANS = kN (Round to 3 decimal places)
Safety = 5.000
Rod diameter = 3.000cm = 0.03m
Ultimate Strength
= 630.000MPa = 630000Pa

Allowable strength
= Ultimate strength/ Factor of safety
= 630000/5
= 126000

Load = Allowable strength * Area
Area = pi * d^2/ 4
= 126000 * 3.1416 * .03^2/ 4
= 126000 * 3.1416 * .0009/ 4
= 356.25744/ 4
ANS = 89.0643kN
Please check. Thank you.

asked by Danny

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