1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN.
ANS= MPa (Round to 3 decimal places)
Diameter = 33.000mm = 0.033m
30.000kN = 30000N
Area = pi*d^2/4
= 3.1416 * 0.033^2/ 4
= 3.1416 *0.001089/ 4
= 0.0034212024/ 4
= 8.553006*10^-4
= 0.0008553
Stress= Load/Area
= 30000/ 0.0008553
= 35075412.14Pa
= 35075.41214kPa
ANS = 35.07541214MPa
2) Consider that the rod was originally 1.000 meters long, and it was stretched 1.110mm by the pulling force. Calculate the strain produced in the rod.
ANS=(6decimal places)
1.110mm = 0.00111m
= 0.00111m/1m
ANS = 0.001110
Please check. Thank you.
Correct
1) To calculate the tensile stress in a rod, you need to divide the force applied (load) by the cross-sectional area of the rod.
Step 1: Convert the diameter from millimeters to meters.
Diameter = 33.000mm = 33.000/1000 m = 0.033m
Step 2: Convert the pull force from kilonewtons to newtons.
30.000kN = 30,000N
Step 3: Calculate the cross-sectional area of the rod.
Area = π * (diameter^2) / 4
Area = π * (0.033^2) / 4
Area = π * 0.001089 / 4
Area = 0.0034212024 / 4
Area ≈ 0.0008553 m^2
Step 4: Calculate the stress.
Stress = Load / Area
Stress = 30,000N / 0.0008553 m^2
Stress ≈ 35,075.41214 Pa
Rounded to 3 decimal places: Stress ≈ 35.075 MPa
2) To calculate the strain produced in the rod, you need to divide the elongation (change in length) by the original length of the rod.
Given:
Original length = 1.000 meters
Elongation = 1.110mm = 0.00111 meters
Step 1: Calculate the strain.
Strain = Elongation / Original length
Strain = 0.00111 / 1.000
Strain = 0.00111
Answer: The strain produced in the rod is approximately 0.00111.