How much heat must be added to 1.0 kg of iron to raise its temperature from 20°C to 95°C? (ciron = 0.11 cal/g•°C)

ΔQ = m•c•ΔT =1000•0.11•(95-20)=8250 cal

Well, well, well, looks like we've got some hot iron in here! Alright, let's calculate the heat.

First things first, we need to convert the units. The specific heat capacity of iron is given in cal/g•°C, but we need it in a more convenient unit. So, let's convert it to cal/kg•°C.

Since there are 1000 grams in 1 kilogram, the specific heat capacity of iron in cal/kg•°C is 0.11 * 1000 = 110 cal/kg•°C.

Now, let's calculate the heat using the equation:

Heat = (mass of iron) * (specific heat capacity of iron) * (change in temperature)

Plugging in the values, we have:

Heat = 1.0 kg * 110 cal/kg•°C * (95°C - 20°C)

Heat = 1.0 kg * 110 cal/kg•°C * 75°C

Heat = 8250 cal

So, my metallic friend, you need to add around 8250 calories of heat to your 1.0 kg of iron to raise its temperature from 20°C to 95°C. Just be careful not to touch it, unless you want a hot surprise!

To calculate the amount of heat required to raise the temperature of a substance, you can use the formula: Q = mcΔT, where Q is the heat added or removed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Given:
Mass of iron (m) = 1.0 kg
Specific heat capacity of iron (c) = 0.11 cal/g•°C
Change in temperature (ΔT) = (95°C - 20°C) = 75°C

First, we need to convert the mass from kg to grams because the specific heat capacity is given in cal/g•°C:
m = 1.0 kg = 1000 g

Next, we can substitute the values into the formula:
Q = mcΔT
Q = (1000 g)(0.11 cal/g•°C)(75°C)

Calculating the answer:
Q = 8250 cal

Therefore, the amount of heat that must be added to 1.0 kg of iron to raise its temperature from 20°C to 95°C is 8250 cal.

To calculate the amount of heat needed to raise the temperature of a substance, you can use the equation:

Q = m * c * ΔT

Where:
Q = heat energy
m = mass of the substance
c = specific heat capacity of the substance
ΔT = change in temperature

In this case, you want to calculate the heat energy (Q) required to raise the temperature of 1.0 kg (1000 g) of iron from 20°C to 95°C. The specific heat capacity (c) of iron is given as 0.11 cal/g•°C.

First, let's calculate the change in temperature (ΔT):

ΔT = final temperature - initial temperature
ΔT = 95°C - 20°C
ΔT = 75°C

Next, substitute the values into the equation:

Q = m * c * ΔT
Q = 1000 g * 0.11 cal/g•°C * 75°C
Q ≈ 8250 cal

Therefore, approximately 8250 calories of heat must be added to 1.0 kg of iron to raise its temperature from 20°C to 95°C.