A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced.
ANS 1 = kPa (3 decimal places)
ANS 2 = (6 decimal places)
1.000cm = 0.01m
2.900cm = 0.029m
length = 1m
Bar extension = 1.500mm = 0.0015m
Area = w * h
= 0.01 * 0.029
= 0.00029
Stress = Load/ Area
= 189000.000N/ 0.000290
= 651724137.9Pa
ANS = 651724.1379kPa
Strain = 0.0015/ 8.7
= 1.7241 * 10^-4
ANS = 0.000172
Please check. Thank you.
Your calculations are correct. Here's how you arrived at the answers:
To calculate stress, you first need to calculate the cross-sectional area of the steel bar using the formula:
Area = width * height
Area = 0.01m * 0.029m = 0.00029 m^2
Next, you can calculate stress using the formula:
Stress = Load / Area
Stress = 189000 N / 0.00029 m^2 = 651724137.9 Pa
Converting to kPa, we get 651724.1379 kPa (rounded to 3 decimal places).
To calculate strain, you divide the bar's extension by its original length:
Strain = Extension / Length
Strain = 0.0015 m / 8.7 m = 1.724137931 × 10^-4
This can be approximated to 0.000172 (rounded to 6 decimal places).
So, the stress produced is 651724.1379 kPa, and the strain produced is approximately 0.000172.