physics
the man hanging upside down is holding a partner who weighs 491 N. Assume that the partner moves on a circle that has a radius of 5.09 m. At a swinging speed of 4.20 m/s, what force must the man apply to his partner in the straightdown position?
asked by
damien

Weight =W= mg
m=W/g =491 / 9.8 =50.1 kg
F = mv²/ r=173.6
=50.1•4.2²/5.09 = 173.6 N
since his partner is in the straightdown position, the man also has to apply force to keep his partner from falling down due to gravity, so you have to add the partner's weight:
Force total = 173.6 + 491 = 664.6 N
posted by Elena
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