The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm?

ANS = kN (Round to 3 decimal place)

Ultimate strength = 600.000MPa = 600000000Pa = 600 * 10^6
Factor of Safety = 3.000
Rod diameter = 6.000cm = .06m

Allowable Strength
= Ultimate strength/ Factor of Safety
= 600* 10^6/ 3 = 200 * 10^6 (or)
= 600000000/3 = 200000000
Allowable Strength
= Load/ Area
Load
= Allowable Strength * Area
= Allowable Strength * (pi*d^2/4)
=200*10^6*pi*.06^2/4
=200000000*3.1416*.0036/4
=2261952/4
=565488N
=565.488kN
Please check. Thank you.

To calculate the maximum permissible load for the steel rod, we need to consider the ultimate strength of the rod, the factor of safety, and the diameter of the rod. Here's how you can calculate it:

1. Convert the ultimate strength of the rod to pascals (Pa):
Ultimate strength = 600.000 MPa = 600 * 10^6 Pa

2. Determine the factor of safety:
Factor of Safety = 3.000

3. Convert the diameter of the rod to meters:
Rod diameter = 6.000 cm = 0.06 m

4. Calculate the allowable strength:
Allowable Strength = Ultimate strength / Factor of Safety
Allowable Strength = 600 * 10^6 / 3 = 200 * 10^6 Pa

5. Calculate the area of the rod:
Area = π * (diameter/2)^2
Area = π * (0.06/2)^2
Area = π * 0.0036
Area = 0.01130973 m^2

6. Calculate the maximum permissible load:
Load = Allowable Strength * Area
Load = 200 * 10^6 * 0.01130973
Load = 2.2619472 * 10^6 N
Load ≈ 2.262 MN (rounded to 3 decimal places)

Therefore, the maximum permissible load for the steel rod is approximately 2.262 kN.