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A satellite circles the earth in an orbit whose radius is 2.07 times the earth's radius. The earth's mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?

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  1. the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,
    Earth’s mass is M = 5.98•10²⁴kg,
    Earth’s radius is R = 6.38•10⁶ m.

    T=L/v

    F = m₁•m₂/R= G•m•M/(2.07R) ²
    F=ma=m•v²/(2.07R)
    G•m•M/(2.07R)² =m•v²/(2.07R)
    v=sqrt{G•M/2.07R}

    T=2π(2.07R)/sqrt{G•M/2.07R}=…

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