a 3.6 kg object is accelerated from rest to a speed of 34.4 m/s in 42 s. What average force was exerted on the object during this period of acceleration. Answer in units of N.
F = m*a
a = V-Vo)/t = (34.4-0)/42 = 0.819 m/s^2.
F = 3.6*0.819 = 2.95 N.
Well, well, well, we have ourselves a physics problem here! Let's see if we can add a little humor into the mix while tackling this question.
So, we have an object that weighs 3.6 kg and it's being accelerated to a speed of 34.4 m/s in 42 seconds. To find the average force, we can use Newton's second law of motion, which states that force is equal to mass times acceleration. In this case, the acceleration is the change in velocity divided by the time taken: (34.4 m/s - 0 m/s) / 42 s.
Now, let's plug in the numbers and calculate, shall we?
Force = mass × acceleration
Force = 3.6 kg × ((34.4 m/s - 0 m/s) / 42 s)
*calculating intensely*
Alright, the grand total is in! The average force exerted on the object during this period of acceleration is approximately 3.028 N.
So, there you have it – the answer in units of N. I hope I was able to amuse you while providing the solution! If you have any more questions or need further assistance, feel free to ask.
To find the average force exerted on the object, we can use Newton's second law of motion, which states that the force exerted on an object is equal to its mass multiplied by its acceleration.
Given:
Mass of the object (m) = 3.6 kg
Final velocity (v) = 34.4 m/s
Time taken (t) = 42 s
Initial velocity (u) = 0 m/s (since the object starts from rest)
So, the acceleration (a) can be found using the equation:
a = (v - u) / t
Substituting the given values:
a = (34.4 m/s - 0 m/s) / 42 s
a = 34.4 m/s / 42 s
a ≈ 0.819 m/s²
Now, we can calculate the average force (F) exerted on the object using the equation:
F = m * a
Substituting the given values:
F = 3.6 kg * 0.819 m/s²
F ≈ 2.95 N
Therefore, the average force exerted on the object during this period of acceleration is approximately 2.95 N.
To find the average force exerted on the object, we can use Newton's second law of motion, which states that the force on an object is equal to its mass multiplied by its acceleration:
F = m * a
Here, the mass of the object, m, is given as 3.6 kg. To find the acceleration, we can use the formula for average acceleration:
a = (v - u) / t
Where:
v = final velocity = 34.4 m/s
u = initial velocity = 0 m/s (since the object starts from rest)
t = time taken = 42 s
Substituting the given values into the formula, we get:
a = (34.4 m/s - 0 m/s) / 42 s
a = 34.4 m/s / 42 s
a ≈ 0.819 m/s²
Now, we can substitute the values of mass (m) and acceleration (a) into the equation for force (F):
F = m * a
F = 3.6 kg * 0.819 m/s²
F ≈ 2.9484 N
Therefore, the average force exerted on the object during the period of acceleration is approximately 2.9484 Newtons (N).