A special type of password consists of four different letters of the alphabet, where each letter is used only once. How many different possible passwords are there?
CORRECTION:BCD should be BCDA
6! - (50%4) =
Azxcvy
I'm sorry, I don't understand the context of your response. Could you please provide more information or clarification?
To solve this problem, we can break it down step by step:
Step 1: Determine the number of choices for the first letter.
Since there are 26 letters in the alphabet, and we need to choose 1 letter, we have 26 choices for the first letter.
Step 2: Determine the number of choices for the second letter.
After choosing the first letter, there are only 25 letters left in the alphabet. Therefore, we have 25 choices for the second letter.
Step 3: Determine the number of choices for the third letter.
After choosing the first and second letters, there are now 24 letters left. Hence, we have 24 choices for the third letter.
Step 4: Determine the number of choices for the fourth letter.
After choosing the first three letters, there are 23 letters remaining. Thus, we have 23 choices for the fourth letter.
Step 5: Calculate the total number of possible passwords.
To find the total number of possible passwords, we multiply the number of choices for each step together:
Total number of passwords = (number of choices for the first letter) * (number of choices for the second letter) * (number of choices for the third letter) * (number of choices for the fourth letter)
= 26 * 25 * 24 * 23
Now, let's calculate the total number of possible passwords:
Total number of possible passwords = 26 * 25 * 24 * 23
= 358,800
Therefore, there are 358,800 different possible passwords.
8 different passwords were formed:
ABCD
BCD
CDAB
DABC.
DCBA
CBAD
BADC
ADCB