How do I calcuate this?
How much heat is gained (in Joules) by the water (qwater) when a chemical reaction takes place in 100.0 mL aqueous solution and has a temperature increase of 13.26 °C? (Remember cwater = 4.180 J/°Cg)
If the density of H2O is 1.0 g/mL, then 100.0 mL H2O has a mass of 100.0 grams.
Then q = mass x specific heat x delta T.
5542.68
To calculate the amount of heat gained by the water (qwater) when a chemical reaction takes place, you can use the formula:
qwater = mwater * cwater * ΔT
where:
qwater = heat gained/lost by the water (in Joules)
mwater = mass of water (in grams)
cwater = specific heat capacity of water (in J/°Cg)
ΔT = change in temperature (in °C)
In this case, you are given the volume of the aqueous solution instead of the mass of water. To convert the volume to mass, you can use the density of water, which is 1 g/mL.
First, convert the volume of the aqueous solution to the mass of water:
mass of water (mwater) = volume of solution * density of water
mass of water = 100.0 mL * 1 g/mL = 100.0 grams
Now, you can substitute the values into the formula:
qwater = mwater * cwater * ΔT
qwater = 100.0 g * 4.180 J/°Cg * 13.26 °C
qwater ≈ 55084.8 Joules
Therefore, the amount of heat gained by the water (qwater) in this chemical reaction is approximately 55084.8 Joules.