Physics(Stress&Strain)

What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm.
ANS = (Round to 3 decimal places)

Load = 65000.000N
ultimate strength = 630.000MPa = 600000000Pa
Area = 5.300cm = 0.053m
Factor of safety
= ultimate strength/ Allowable strength
= ultimate strength * Area/ Load
= 630000000 * 0.053/ 65000.000
= 33390000/ 65000.000
= 513.692
ANS = 5.136
Please check. Thank you.

asked by Danny

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