A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 5.95 m/s. The car is a distance d away. The bear is 37.0 m behind the tourist and running at 7.80 m/s. The tourist reaches the car safely. What is the maximum possible value for d?
V1*t = V2*t-37 m.
5.95t = 7.80t-37
7.8t-5.95t = 37
1.85t = 37
t = 20 s.
d = 5.95 * 20 = 119 m