how many grams of copper is displaced from copper sulphate solution by adding 27 grams of aluminium
forget grams. Convert to moles.
Then use the equation to determine how many moles of copper are used for each mole of aluminum.
Then convert that back to grams.
Do it correctly stupid
To determine how many grams of copper are displaced from copper sulfate solution by adding 27 grams of aluminum, we need to first understand the reaction that takes place between aluminum and copper sulfate.
The reaction between aluminum and copper sulfate can be represented by the following equation:
2 Al + 3 CuSO4 → Al2(SO4)3 + 3 Cu
From the equation, we can see that 2 moles of aluminum react with 3 moles of copper sulfate to produce 1 mole of aluminum sulfate and 3 moles of copper.
To calculate the mass of copper displaced, we need to find the molar mass of copper and use the mole ratio in the balanced equation.
The molar mass of copper (Cu) is approximately 63.55 grams/mole.
Now, let's calculate:
1. Calculate the number of moles of aluminum used:
Moles of aluminum = Mass of aluminum / molar mass of aluminum
Moles of aluminum = 27 grams / 26.98 grams/mole ≈ 1 mole (rounded to whole number)
2. Use the mole ratio from the balanced equation to find the number of moles of copper displaced:
Moles of copper = Moles of aluminum × (3 moles of Cu / 2 moles of Al)
Moles of copper = 1 mole × (3 moles of Cu / 2 moles of Al) = 1.5 moles
3. Calculate the mass of copper displaced:
Mass of copper = Moles of copper × molar mass of copper
Mass of copper = 1.5 moles × 63.55 grams/mole ≈ 95.33 grams (rounded to two decimal places)
Therefore, approximately 95.33 grams of copper are displaced from the copper sulfate solution by adding 27 grams of aluminum.