If you weigh out 2.083 g Fe(NO3)3·9H2O, what is the final concentration of the dilute Fe(NO3)3 solution that you make?
How much water did you add? How many dilutions did you make?
we did 1 dilution and do you need to know how much water is added? I attempted the problem and the hint that was given said..."use the mass of iron nitrate and the volume of your final solution to determine the concentration of the final solution."
we needed to make the solution's concentration about 0.002 M.
Yes, the final volume of the solution is needed.
Convert 2.083g Fe(NO3)3.9H2O to mols. That's mols = grams/molar mass.
Then mols Fe(NO)3)3 is the same as mols of the stating material.
Finally, mols/L = M.