Physics (Stress & Strain)

A uniform bar 1.900 meters in length and having a cross sectional area of 11.000cm^2 is subject to a loading of 5450.000 Newtons. this load causes an extension to the bar length of 2.420mm. Calculate the stress and strain produced.
11cm = .11m
2.420mm = .02420m
length = 1.9m

Area = L * W
= 1.9m * .11m
= .209m
Stress
= load/ Area
= 5450.000N/.209m
= 26076.555Pa
ANS = 26.076555kPa
Strain
= .02420m/1.9m
ANS = .0127368
Is this done correctly? Thank you.

asked by Danny
  1. OK

    posted by Elena

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