Someone help!
A jeepney moves along a straight line at an average speed of 10 m/s. What is the distance traveled by the jeepney in 2.5 h?
2.5 h = 9000s
10m/s x 9000s = 90000m
To find the distance traveled by the jeepney, we can use the formula:
Distance = Average Speed × Time
Given:
Average Speed = 10 m/s
Time = 2.5 h
First, let's convert the time from hours to seconds since the average speed is given in meters per second.
1 hour = 3600 seconds
So, 2.5 hours = 2.5 × 3600 seconds = 9000 seconds.
Now, we can substitute the values into the formula:
Distance = 10 m/s × 9000 s
Calculating the product:
Distance = 90,000 meters
Therefore, the jeepney travels a distance of 90,000 meters in 2.5 hours.
To find the distance traveled by the jeepney, we need to use the formula:
Distance = Speed × Time
In this case, the speed of the jeepney is given as 10 m/s and the time is given as 2.5 hours. However, we need to ensure that the units of time and speed are consistent.
Since the speed is given in meters per second (m/s), we need to convert the time from hours to seconds. Since 1 hour is equal to 3600 seconds, we can multiply the given time by 3600 to convert it into seconds:
Time in seconds = 2.5 hours × 3600 seconds/hour = 9000 seconds
Now we can use the formula to find the distance traveled:
Distance = Speed × Time = 10 m/s × 9000 seconds
Calculating this, we find:
Distance = 10 m/s × 9000 seconds = 90,000 meters
Therefore, the distance traveled by the jeepney in 2.5 hours is 90,000 meters.
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