Do I solve this by multiplying 1.8645 by 1.14??The equation of your calibration curve from a spectrophotometry experiment was y = 1.8645x. Assuming your calibration curve is set up exactly like it was in lab (concentration in mM on the x axis and absorbance on the y axis), what would the concentration of a solution be if the measured absorbance was 1.14A?
The equation of straight line is y = mx + b and this one is y = 1.8645x
y = absorbance; x = concn in mM = C.
Then 1.14 = 1.8645*C
Solve for C.
C = 1.14/1.8645
The equation of your calibration curve from a spectrophotometry experiment was y = 1.8645x. Assuming your calibration curve is set up exactly like it was in lab (concentration in mM on the x axis and absorbance on the y axis), what would the concentration of a solution be if the measured absorbance was 0.92A?
Yes, to find the concentration of the solution, you can multiply the measured absorbance (1.14A) by the slope of the calibration curve (1.8645).
The equation y = 1.8645x represents a linear relationship between the concentration (x) in mM and the absorbance (y) of the solution. The slope of the calibration curve, 1.8645, represents the change in absorbance per unit change in concentration.
To find the concentration, you can use this formula:
concentration = absorbance * slope
Substituting the given values:
concentration = 1.14A * 1.8645
Now you can use a calculator to multiply 1.14 by 1.8645 to find the concentration of the solution.