what is the potential energy of a 500g flag at the top of a 5.5m tall flag
GIVEN m=500g=(500/1000)kg=0.5kg
h=5.5m
Also we know, g=9.8m/s^2
potential energy, PE=m*g*h
=0.5*9.8*5.5
=26.95J
PE=mgh
To calculate the potential energy of an object, we need to use the formula:
Potential Energy (PE) = mass (m) × acceleration due to gravity (g) × height (h)
In this case, we have a flag with a mass of 500 grams and a height of 5.5 meters. However, we need to convert the mass to kilograms to be consistent with the SI unit system:
Mass (m) = 500 grams ÷ 1000 grams/kg = 0.5 kg
Acceleration due to gravity (g) is approximately 9.8 meters per second squared (m/s²).
Now we can calculate the potential energy:
PE = 0.5 kg × 9.8 m/s² × 5.5 m
PE ≈ 26.95 Joules
Therefore, the potential energy of the flag at the top of the 5.5 meter tall flagpole is approximately 26.95 Joules.