Children's tickets to a movie cost $7.00. Adult tickets cost $12.00. If 1275 tickets were sold for a total of $2490.00, how many of each type were sold?

There must be a typo, because the cheapest ticket is $7, which when multiplied by 1275 gives 8925, much higher than the revenue of $2490.

Assuming total of 275 tickets sold.

x=number of adult tickets
275-x=number of children's tickets

Then
12x+7(275-x)=2490
Solve for x to get x=113
so
113 adult tickets,
162 children's tickets.

My bad...

To solve this problem, we can set up a system of equations based on the given information. Let's assign variables to represent the number of children's tickets and adult tickets sold.

Let x represent the number of children's tickets sold.
Let y represent the number of adult tickets sold.

We can now set up two equations based on the given information:

Equation 1: The total number of tickets sold is 1275.
x + y = 1275

Equation 2: The total amount collected from ticket sales is $2490.
7x + 12y = 2490

Now we have a system of two equations with two variables. We can solve this system to find the values of x and y.

One method to solve this system is substitution. Let's solve Equation 1 for x and substitute it into Equation 2.

From Equation 1: x = 1275 - y

Substituting x in Equation 2:
7(1275 - y) + 12y = 2490

Simplifying:
8925 - 7y + 12y = 2490
-5y = -6435
y = 6435/5
y = 1287

Now we know that y, the number of adult tickets sold, is 1287. We can substitute this value back into Equation 1 to solve for x.

x + 1287 = 1275
x = 1275 - 1287
x = -12

Since the number of tickets cannot be negative, we made an error somewhere. Let's go back and check our calculations.

There is a discrepancy between the given information and the equation set up. It is not possible for the total number of tickets sold to be 1275 if the number of tickets sold is a whole number. Please double-check the accuracy of the given information or provide additional details.