give the number whose hundred place is one-third of the greatest one-digit number, the tens place is twice the hundred place, the ones place is four times the digit in the hundreds place divided by 2, and the three digits in the thousands period is the product of the digits in the units period?
filling in blanks as we read the conditions, we get
3xx
36x
366
72366
To find the number that satisfies the given conditions, we'll follow the step-by-step explanations provided:
1. The hundred place is one-third of the greatest one-digit number:
The greatest one-digit number is 9. One-third of 9 is (9/3)=3.
2. The tens place is twice the hundred place:
Since the hundred place is 3, twice that would be 2*3=6.
3. The ones place is four times the digit in the hundreds place divided by 2:
The digit in the hundreds place is 3, so four times that is 4*3=12. Then, 12/2=6.
4. The three digits in the thousands period is the product of the digits in the units period:
The units period refers to the ones place. Previously, we found the ones place to be 6. So, the three digits in the thousands period are the product of 6, which is 6*6*6=216.
Therefore, the number that satisfies all the given conditions is 21636.